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40132133413901 is a prime number
BaseRepresentation
bin10010001111111111111011…
…00011100110010000001101
312021002121001101020220121222
421013333331203212100031
520230011102123221101
6221204240401533125
711311310451402464
oct1107777543462015
9167077041226558
1040132133413901
1111872a40084691
124601a623441a5
1319515a0458c89
149ca59704b9db
15498ddeee801b
hex247ffd8e640d

40132133413901 has 2 divisors, whose sum is σ = 40132133413902. Its totient is φ = 40132133413900.

The previous prime is 40132133413829. The next prime is 40132133413903. The reversal of 40132133413901 is 10931433123104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28493187085801 + 11638946328100 = 5337901^2 + 3411590^2 .

It is a cyclic number.

It is not a de Polignac number, because 40132133413901 - 242 = 35734086902797 is a prime.

It is a super-2 number, since 2×401321334139012 (a number of 28 digits) contains 22 as substring.

Together with 40132133413903, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40132133413903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066066706950 + 20066066706951.

It is an arithmetic number, because the mean of its divisors is an integer number (20066066706951).

Almost surely, 240132133413901 is an apocalyptic number.

It is an amenable number.

40132133413901 is a deficient number, since it is larger than the sum of its proper divisors (1).

40132133413901 is an equidigital number, since it uses as much as digits as its factorization.

40132133413901 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 35.

The spelling of 40132133413901 in words is "forty trillion, one hundred thirty-two billion, one hundred thirty-three million, four hundred thirteen thousand, nine hundred one".