Base | Representation |
---|---|
bin | 10010010000000000001011… |
… | …11010011011101001100111 |
3 | 12021002121102011001222211021 |
4 | 21020000011322123221213 |
5 | 20230011344021230021 |
6 | 221204302330552011 |
7 | 11311314103201405 |
oct | 1110000572335147 |
9 | 167077364058737 |
10 | 40132273617511 |
11 | 11873002235739 |
12 | 4601aa1298607 |
13 | 19515c3507baa |
14 | 9ca5ab906475 |
15 | 498dec48ec41 |
hex | 248005e9ba67 |
40132273617511 has 2 divisors, whose sum is σ = 40132273617512. Its totient is φ = 40132273617510.
The previous prime is 40132273617509. The next prime is 40132273617521. The reversal of 40132273617511 is 11571637223104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40132273617511 - 21 = 40132273617509 is a prime.
It is a super-2 number, since 2×401322736175112 (a number of 28 digits) contains 22 as substring.
Together with 40132273617509, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40132273617521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066136808755 + 20066136808756.
It is an arithmetic number, because the mean of its divisors is an integer number (20066136808756).
Almost surely, 240132273617511 is an apocalyptic number.
40132273617511 is a deficient number, since it is larger than the sum of its proper divisors (1).
40132273617511 is an equidigital number, since it uses as much as digits as its factorization.
40132273617511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 211680, while the sum is 43.
The spelling of 40132273617511 in words is "forty trillion, one hundred thirty-two billion, two hundred seventy-three million, six hundred seventeen thousand, five hundred eleven".
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