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40132518824861 is a prime number
BaseRepresentation
bin10010010000000000101001…
…00001110100101110011101
312021002122001020110211001222
421020000110201310232131
520230012344304343421
6221204342530343125
711311323141342551
oct1110002441645635
9167078036424058
1040132518824861
1111873118695641
124601b4b42aaa5
13195163225ccb8
149ca5d22d5861
15498e13c78cab
hex248014874b9d

40132518824861 has 2 divisors, whose sum is σ = 40132518824862. Its totient is φ = 40132518824860.

The previous prime is 40132518824843. The next prime is 40132518824887. The reversal of 40132518824861 is 16842881523104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39461249948761 + 671268876100 = 6281819^2 + 819310^2 .

It is a cyclic number.

It is not a de Polignac number, because 40132518824861 - 234 = 40115338955677 is a prime.

It is a super-2 number, since 2×401325188248612 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40132518824161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066259412430 + 20066259412431.

It is an arithmetic number, because the mean of its divisors is an integer number (20066259412431).

Almost surely, 240132518824861 is an apocalyptic number.

It is an amenable number.

40132518824861 is a deficient number, since it is larger than the sum of its proper divisors (1).

40132518824861 is an equidigital number, since it uses as much as digits as its factorization.

40132518824861 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2949120, while the sum is 53.

The spelling of 40132518824861 in words is "forty trillion, one hundred thirty-two billion, five hundred eighteen million, eight hundred twenty-four thousand, eight hundred sixty-one".