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40133114893 is a prime number
BaseRepresentation
bin100101011000000111…
…101011110000001101
310211120221112110210201
4211120013223300031
51124143034134033
630234211533501
72620351563604
oct453007536015
9124527473721
1040133114893
1116025108253
1279405ba291
133a2781ba81
141d2a13ca3b
15109d52d47d
hex9581ebc0d

40133114893 has 2 divisors, whose sum is σ = 40133114894. Its totient is φ = 40133114892.

The previous prime is 40133114891. The next prime is 40133115073. The reversal of 40133114893 is 39841133104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21809973124 + 18323141769 = 147682^2 + 135363^2 .

It is a cyclic number.

It is not a de Polignac number, because 40133114893 - 21 = 40133114891 is a prime.

It is a super-2 number, since 2×401331148932 (a number of 22 digits) contains 22 as substring.

Together with 40133114891, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40133114891) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066557446 + 20066557447.

It is an arithmetic number, because the mean of its divisors is an integer number (20066557447).

Almost surely, 240133114893 is an apocalyptic number.

It is an amenable number.

40133114893 is a deficient number, since it is larger than the sum of its proper divisors (1).

40133114893 is an equidigital number, since it uses as much as digits as its factorization.

40133114893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 37.

Adding to 40133114893 its reverse (39841133104), we get a palindrome (79974247997).

The spelling of 40133114893 in words is "forty billion, one hundred thirty-three million, one hundred fourteen thousand, eight hundred ninety-three".