40133202040 has 64 divisors (see below), whose sum is σ = 93217845600. Its totient is φ = 15541112832.

The previous prime is 40133202019. The next prime is 40133202049. The reversal of 40133202040 is 4020233104.

It is a super-2 number, since 2×40133202040² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40133201999 and 40133202017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40133202049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 91116 + ... + 297604.

Almost surely, 2^40133202040 is an apocalyptic number.

40133202040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 40133202040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (46608922800).

40133202040 is an abundant number, since it is smaller than the sum of its proper divisors (53084643560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

40133202040 is a wasteful number, since it uses less digits than its factorization.

40133202040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 206656 (or 206652 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 40133202040 its reverse (4020233104), we get a palindrome (44153435144).

The spelling of 40133202040 in words is "forty billion, one hundred thirty-three million, two hundred two thousand, forty".