Base | Representation |
---|---|
bin | 100101011000001011… |
… | …111110101101110101 |
3 | 10211121000122200201121 |
4 | 211120023332231311 |
5 | 1124143331204031 |
6 | 30234252023541 |
7 | 2620364264251 |
oct | 453013765565 |
9 | 124530580647 |
10 | 40134241141 |
11 | 16025807435 |
12 | 7940a61bb1 |
13 | 3a27b245a7 |
14 | 1d2a353261 |
15 | 109d6a2011 |
hex | 9582feb75 |
40134241141 has 2 divisors, whose sum is σ = 40134241142. Its totient is φ = 40134241140.
The previous prime is 40134241097. The next prime is 40134241153. The reversal of 40134241141 is 14114243104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36193540516 + 3940700625 = 190246^2 + 62775^2 .
It is a cyclic number.
It is not a de Polignac number, because 40134241141 - 27 = 40134241013 is a prime.
It is a super-3 number, since 3×401342411413 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40134251141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20067120570 + 20067120571.
It is an arithmetic number, because the mean of its divisors is an integer number (20067120571).
Almost surely, 240134241141 is an apocalyptic number.
It is an amenable number.
40134241141 is a deficient number, since it is larger than the sum of its proper divisors (1).
40134241141 is an equidigital number, since it uses as much as digits as its factorization.
40134241141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 40134241141 its reverse (14114243104), we get a palindrome (54248484245).
The spelling of 40134241141 in words is "forty billion, one hundred thirty-four million, two hundred forty-one thousand, one hundred forty-one".
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