4014054411503 has 2 divisors, whose sum is σ = 4014054411504. Its totient is φ = 4014054411502.

The previous prime is 4014054411473. The next prime is 4014054411511. The reversal of 4014054411503 is 3051144504104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4014054411503 - 2²⁶ = 4013987302639 is a prime.

It is a super-2 number, since 2×4014054411503² (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4014054411503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4014054411533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007027205751 + 2007027205752.

It is an arithmetic number, because the mean of its divisors is an integer number (2007027205752).

Almost surely, 2^{4014054411503} is an apocalyptic number.

4014054411503 is a deficient number, since it is larger than the sum of its proper divisors (1).

4014054411503 is an equidigital number, since it uses as much as digits as its factorization.

4014054411503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 4014054411503 its reverse (3051144504104), we get a palindrome (7065198915607).

The spelling of 4014054411503 in words is "four trillion, fourteen billion, fifty-four million, four hundred eleven thousand, five hundred three".