4014111252197 has 2 divisors, whose sum is σ = 4014111252198. Its totient is φ = 4014111252196.

The previous prime is 4014111252191. The next prime is 4014111252241. The reversal of 4014111252197 is 7912521114104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2938159379236 + 1075951872961 = 1714106^2 + 1037281^2 .

It is a cyclic number.

It is not a de Polignac number, because 4014111252197 - 2¹⁶ = 4014111186661 is a prime.

It is a super-3 number, since 3×4014111252197³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 4014111252197.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4014111252191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007055626098 + 2007055626099.

It is an arithmetic number, because the mean of its divisors is an integer number (2007055626099).

Almost surely, 2^{4014111252197} is an apocalyptic number.

It is an amenable number.

4014111252197 is a deficient number, since it is larger than the sum of its proper divisors (1).

4014111252197 is an equidigital number, since it uses as much as digits as its factorization.

4014111252197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 38.

The spelling of 4014111252197 in words is "four trillion, fourteen billion, one hundred eleven million, two hundred fifty-two thousand, one hundred ninety-seven".