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40141233212153 is a prime number
BaseRepresentation
bin10010010000010000110111…
…11100100100101011111001
312021010110112120010120002212
421020020123330210223321
520230133221200242103
6221212343350104505
711312052115405523
oct1110103374445371
9167113476116085
1040141233212153
111187688a739807
12460378194b135
1319523c07abc98
149cabbb800a13
15499273d397d8
hex24821bf24af9

40141233212153 has 2 divisors, whose sum is σ = 40141233212154. Its totient is φ = 40141233212152.

The previous prime is 40141233212057. The next prime is 40141233212159. The reversal of 40141233212153 is 35121233214104.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26551481812969 + 13589751399184 = 5152813^2 + 3686428^2 .

It is a cyclic number.

It is not a de Polignac number, because 40141233212153 - 210 = 40141233211129 is a prime.

It is a super-2 number, since 2×401412332121532 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40141233212159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20070616606076 + 20070616606077.

It is an arithmetic number, because the mean of its divisors is an integer number (20070616606077).

Almost surely, 240141233212153 is an apocalyptic number.

It is an amenable number.

40141233212153 is a deficient number, since it is larger than the sum of its proper divisors (1).

40141233212153 is an equidigital number, since it uses as much as digits as its factorization.

40141233212153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 40141233212153 its reverse (35121233214104), we get a palindrome (75262466426257).

The spelling of 40141233212153 in words is "forty trillion, one hundred forty-one billion, two hundred thirty-three million, two hundred twelve thousand, one hundred fifty-three".