Base | Representation |
---|---|
bin | 10010010000010001000100… |
… | …01010100111011100001111 |
3 | 12021010110210211110210222121 |
4 | 21020020202022213130033 |
5 | 20230133424403304001 |
6 | 221212401554353411 |
7 | 11312054523334264 |
oct | 1110104212473417 |
9 | 167113724423877 |
10 | 40141337556751 |
11 | 11876933628412 |
12 | 46037b088b867 |
13 | 19524092b4152 |
14 | 9cabcb60326b |
15 | 49927d09b6a1 |
hex | 2482222a770f |
40141337556751 has 2 divisors, whose sum is σ = 40141337556752. Its totient is φ = 40141337556750.
The previous prime is 40141337556679. The next prime is 40141337556779. The reversal of 40141337556751 is 15765573314104.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40141337556751 is a prime.
It is a super-2 number, since 2×401413375567512 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40141337556791) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20070668778375 + 20070668778376.
It is an arithmetic number, because the mean of its divisors is an integer number (20070668778376).
Almost surely, 240141337556751 is an apocalyptic number.
40141337556751 is a deficient number, since it is larger than the sum of its proper divisors (1).
40141337556751 is an equidigital number, since it uses as much as digits as its factorization.
40141337556751 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5292000, while the sum is 52.
The spelling of 40141337556751 in words is "forty trillion, one hundred forty-one billion, three hundred thirty-seven million, five hundred fifty-six thousand, seven hundred fifty-one".
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