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40153480049 is a prime number
BaseRepresentation
bin100101011001010101…
…010111101101110001
310211122100212010112202
4211121111113231301
51124213242330144
630240220232545
72621016643334
oct453125275561
9124570763482
1040153480049
1116035657961
12794739b755
133a2bacc467
141d2cb2061b
1510a020264e
hex959557b71

40153480049 has 2 divisors, whose sum is σ = 40153480050. Its totient is φ = 40153480048.

The previous prime is 40153480013. The next prime is 40153480051. The reversal of 40153480049 is 94008435104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38183895649 + 1969584400 = 195407^2 + 44380^2 .

It is a cyclic number.

It is not a de Polignac number, because 40153480049 - 212 = 40153475953 is a prime.

It is a super-2 number, since 2×401534800492 (a number of 22 digits) contains 22 as substring.

Together with 40153480051, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 40153479994 and 40153480021.

It is not a weakly prime, because it can be changed into another prime (40153480009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20076740024 + 20076740025.

It is an arithmetic number, because the mean of its divisors is an integer number (20076740025).

Almost surely, 240153480049 is an apocalyptic number.

It is an amenable number.

40153480049 is a deficient number, since it is larger than the sum of its proper divisors (1).

40153480049 is an equidigital number, since it uses as much as digits as its factorization.

40153480049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 38.

The spelling of 40153480049 in words is "forty billion, one hundred fifty-three million, four hundred eighty thousand, forty-nine".