Base | Representation |
---|---|
bin | 10010010000110101111001… |
… | …00111011100101010110011 |
3 | 12021012100211201022200211202 |
4 | 21020122330213130222303 |
5 | 20230444422310102001 |
6 | 221225431510201415 |
7 | 11313354466144214 |
oct | 1110327447345263 |
9 | 167170751280752 |
10 | 40161108675251 |
11 | 11884259938373 |
12 | 46075aa05326b |
13 | 195423a431935 |
14 | 9cbb4534940b |
15 | 499a38ba596b |
hex | 2486bc9dcab3 |
40161108675251 has 2 divisors, whose sum is σ = 40161108675252. Its totient is φ = 40161108675250.
The previous prime is 40161108675179. The next prime is 40161108675253. The reversal of 40161108675251 is 15257680116104.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40161108675251 is a prime.
It is a super-2 number, since 2×401611086752512 (a number of 28 digits) contains 22 as substring.
Together with 40161108675253, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 40161108675196 and 40161108675205.
It is not a weakly prime, because it can be changed into another prime (40161108675253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20080554337625 + 20080554337626.
It is an arithmetic number, because the mean of its divisors is an integer number (20080554337626).
Almost surely, 240161108675251 is an apocalyptic number.
40161108675251 is a deficient number, since it is larger than the sum of its proper divisors (1).
40161108675251 is an equidigital number, since it uses as much as digits as its factorization.
40161108675251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 47.
The spelling of 40161108675251 in words is "forty trillion, one hundred sixty-one billion, one hundred eight million, six hundred seventy-five thousand, two hundred fifty-one".
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