Base | Representation |
---|---|
bin | 100101011010000010… |
… | …001000101110010111 |
3 | 10211200011221100001021 |
4 | 211122002020232113 |
5 | 1124224243341002 |
6 | 30241315542011 |
7 | 2621221460362 |
oct | 453202105627 |
9 | 124604840037 |
10 | 40165215127 |
11 | 16041242674 |
12 | 794b2ba907 |
13 | 3a3137a9ab |
14 | 1d304d70d9 |
15 | 10a126e737 |
hex | 95a088b97 |
40165215127 has 2 divisors, whose sum is σ = 40165215128. Its totient is φ = 40165215126.
The previous prime is 40165215119. The next prime is 40165215133. The reversal of 40165215127 is 72151256104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40165215127 - 23 = 40165215119 is a prime.
It is a super-2 number, since 2×401652151272 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40165215092 and 40165215101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40165215107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20082607563 + 20082607564.
It is an arithmetic number, because the mean of its divisors is an integer number (20082607564).
Almost surely, 240165215127 is an apocalyptic number.
40165215127 is a deficient number, since it is larger than the sum of its proper divisors (1).
40165215127 is an equidigital number, since it uses as much as digits as its factorization.
40165215127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 34.
The spelling of 40165215127 in words is "forty billion, one hundred sixty-five million, two hundred fifteen thousand, one hundred twenty-seven".
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