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402033131413 is a prime number
BaseRepresentation
bin1011101100110110000…
…10101011111110010101
31102102201101021010222021
411312123002223332111
523041330440201123
6504405205133141
741021520142564
oct5663302537625
91372641233867
10402033131413
111455572490a1
1265b000ba1b1
132bbb0915a94
141565c203bdb
15a6d0152c5d
hex5d9b0abf95

402033131413 has 2 divisors, whose sum is σ = 402033131414. Its totient is φ = 402033131412.

The previous prime is 402033131407. The next prime is 402033131431. The reversal of 402033131413 is 314131330204.

Together with next prime (402033131431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 284560367364 + 117472764049 = 533442^2 + 342743^2 .

It is a cyclic number.

It is not a de Polignac number, because 402033131413 - 213 = 402033123221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (402033134413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201016565706 + 201016565707.

It is an arithmetic number, because the mean of its divisors is an integer number (201016565707).

Almost surely, 2402033131413 is an apocalyptic number.

It is an amenable number.

402033131413 is a deficient number, since it is larger than the sum of its proper divisors (1).

402033131413 is an equidigital number, since it uses as much as digits as its factorization.

402033131413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 402033131413 its reverse (314131330204), we get a palindrome (716164461617).

The spelling of 402033131413 in words is "four hundred two billion, thirty-three million, one hundred thirty-one thousand, four hundred thirteen".