Search a number
-
+
4021341230293 is a prime number
BaseRepresentation
bin111010100001001010100…
…111011001010011010101
3112020102210011222112020221
4322201022213121103111
51011341201323332133
612315213442354341
7563350404321322
oct72411247312325
915212704875227
104021341230293
111310494319882
1254b44305b9b1
13232298315b5a
14dc8c37d9b49
156e90e85ca2d
hex3a84a9d94d5

4021341230293 has 2 divisors, whose sum is σ = 4021341230294. Its totient is φ = 4021341230292.

The previous prime is 4021341230251. The next prime is 4021341230299. The reversal of 4021341230293 is 3920321431204.

4021341230293 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3140132849764 + 881208380529 = 1772042^2 + 938727^2 .

It is a cyclic number.

It is not a de Polignac number, because 4021341230293 - 233 = 4012751295701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4021341230299) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010670615146 + 2010670615147.

It is an arithmetic number, because the mean of its divisors is an integer number (2010670615147).

Almost surely, 24021341230293 is an apocalyptic number.

It is an amenable number.

4021341230293 is a deficient number, since it is larger than the sum of its proper divisors (1).

4021341230293 is an equidigital number, since it uses as much as digits as its factorization.

4021341230293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 34.

Adding to 4021341230293 its reverse (3920321431204), we get a palindrome (7941662661497).

The spelling of 4021341230293 in words is "four trillion, twenty-one billion, three hundred forty-one million, two hundred thirty thousand, two hundred ninety-three".