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4021430345431 is a prime number
BaseRepresentation
bin111010100001001111111…
…011010101111011010111
3112020110000101200001020121
4322201033323111323113
51011341342132023211
612315230344412411
7563352535640242
oct72411773257327
915213011601217
104021430345431
11131052a656354
1254b468a77107
132322b09180c5
14dc8d1596259
156e9175b2271
hex3a84fed5ed7

4021430345431 has 2 divisors, whose sum is σ = 4021430345432. Its totient is φ = 4021430345430.

The previous prime is 4021430345407. The next prime is 4021430345441. The reversal of 4021430345431 is 1345430341204.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4021430345431 - 211 = 4021430343383 is a prime.

It is a super-3 number, since 3×40214303454313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4021430345441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010715172715 + 2010715172716.

It is an arithmetic number, because the mean of its divisors is an integer number (2010715172716).

Almost surely, 24021430345431 is an apocalyptic number.

4021430345431 is a deficient number, since it is larger than the sum of its proper divisors (1).

4021430345431 is an equidigital number, since it uses as much as digits as its factorization.

4021430345431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 34.

Adding to 4021430345431 its reverse (1345430341204), we get a palindrome (5366860686635).

The spelling of 4021430345431 in words is "four trillion, twenty-one billion, four hundred thirty million, three hundred forty-five thousand, four hundred thirty-one".