Base | Representation |
---|---|
bin | 111010100001110010100… |
… | …110100110100111001111 |
3 | 112020111111221100211000001 |
4 | 322201302212212213033 |
5 | 1011344040100030221 |
6 | 12315404205545131 |
7 | 563403131603545 |
oct | 72416246464717 |
9 | 15214457324001 |
10 | 4022012111311 |
11 | 13107a8a8a6a7 |
12 | 54b5ab8751a7 |
13 | 2323742cb27c |
14 | dc948953d95 |
15 | 6e94d6cc391 |
hex | 3a8729a69cf |
4022012111311 has 2 divisors, whose sum is σ = 4022012111312. Its totient is φ = 4022012111310.
The previous prime is 4022012111207. The next prime is 4022012111317. The reversal of 4022012111311 is 1131112102204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4022012111311 - 215 = 4022012078543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4022012111317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011006055655 + 2011006055656.
It is an arithmetic number, because the mean of its divisors is an integer number (2011006055656).
Almost surely, 24022012111311 is an apocalyptic number.
4022012111311 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022012111311 is an equidigital number, since it uses as much as digits as its factorization.
4022012111311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 4022012111311 its reverse (1131112102204), we get a palindrome (5153124213515).
The spelling of 4022012111311 in words is "four trillion, twenty-two billion, twelve million, one hundred eleven thousand, three hundred eleven".
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