40221214181 has 2 divisors, whose sum is σ = 40221214182. Its totient is φ = 40221214180.

The previous prime is 40221214177. The next prime is 40221214183. The reversal of 40221214181 is 18141212204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26702501281 + 13518712900 = 163409^2 + 116270^2 .

It is a cyclic number.

It is not a de Polignac number, because 40221214181 - 2² = 40221214177 is a prime.

It is a super-2 number, since 2×40221214181² (a number of 22 digits) contains 22 as substring.

Together with 40221214183, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 40221214181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40221214183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20110607090 + 20110607091.

It is an arithmetic number, because the mean of its divisors is an integer number (20110607091).

Almost surely, 2^40221214181 is an apocalyptic number.

It is an amenable number.

40221214181 is a deficient number, since it is larger than the sum of its proper divisors (1).

40221214181 is an equidigital number, since it uses as much as digits as its factorization.

40221214181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1024, while the sum is 26.

Adding to 40221214181 its reverse (18141212204), we get a palindrome (58362426385).

The spelling of 40221214181 in words is "forty billion, two hundred twenty-one million, two hundred fourteen thousand, one hundred eighty-one".