Base | Representation |
---|---|
bin | 100101011101010111… |
… | …111010001000011101 |
3 | 10211211002101102011111 |
4 | 211131113322020131 |
5 | 1124333120113143 |
6 | 30251041022021 |
7 | 2622502006462 |
oct | 453527721035 |
9 | 124732342144 |
10 | 40221254173 |
11 | 1606a938631 |
12 | 7966024911 |
13 | 3a3cb6baa9 |
14 | 1d37b23669 |
15 | 10a613d99d |
hex | 95d5fa21d |
40221254173 has 2 divisors, whose sum is σ = 40221254174. Its totient is φ = 40221254172.
The previous prime is 40221254149. The next prime is 40221254219. The reversal of 40221254173 is 37145212204.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29874702649 + 10346551524 = 172843^2 + 101718^2 .
It is a cyclic number.
It is not a de Polignac number, because 40221254173 - 221 = 40219157021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40221252173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20110627086 + 20110627087.
It is an arithmetic number, because the mean of its divisors is an integer number (20110627087).
Almost surely, 240221254173 is an apocalyptic number.
It is an amenable number.
40221254173 is a deficient number, since it is larger than the sum of its proper divisors (1).
40221254173 is an equidigital number, since it uses as much as digits as its factorization.
40221254173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 40221254173 its reverse (37145212204), we get a palindrome (77366466377).
The spelling of 40221254173 in words is "forty billion, two hundred twenty-one million, two hundred fifty-four thousand, one hundred seventy-three".
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