Base | Representation |
---|---|
bin | 111010100010101101101… |
… | …011101110110100110101 |
3 | 112020121002000110222220221 |
4 | 322202231223232310311 |
5 | 1011403102321431123 |
6 | 12320050414454341 |
7 | 563436525634012 |
oct | 72425553566465 |
9 | 15217060428827 |
10 | 4023003311413 |
11 | 1311167542a39 |
12 | 54b8278043b1 |
13 | 2324a1776bc8 |
14 | dca00450709 |
15 | 6e9aa72125d |
hex | 3a8adaeed35 |
4023003311413 has 2 divisors, whose sum is σ = 4023003311414. Its totient is φ = 4023003311412.
The previous prime is 4023003311407. The next prime is 4023003311461. The reversal of 4023003311413 is 3141133003204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3253344512209 + 769658799204 = 1803703^2 + 877302^2 .
It is a cyclic number.
It is not a de Polignac number, because 4023003311413 - 29 = 4023003310901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4023003311813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011501655706 + 2011501655707.
It is an arithmetic number, because the mean of its divisors is an integer number (2011501655707).
Almost surely, 24023003311413 is an apocalyptic number.
It is an amenable number.
4023003311413 is a deficient number, since it is larger than the sum of its proper divisors (1).
4023003311413 is an equidigital number, since it uses as much as digits as its factorization.
4023003311413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 4023003311413 its reverse (3141133003204), we get a palindrome (7164136314617).
The spelling of 4023003311413 in words is "four trillion, twenty-three billion, three million, three hundred eleven thousand, four hundred thirteen".
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