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40230141431 is a prime number
BaseRepresentation
bin100101011101111001…
…110011110111110111
310211211201002221012012
4211131321303313313
51124342404011211
630251555314435
72622640363034
oct453571636767
9124751087165
1040230141431
1116074958777
127968baba1b
133a4196101c
141d38d9838b
1510a6ce6d8b
hex95de73df7

40230141431 has 2 divisors, whose sum is σ = 40230141432. Its totient is φ = 40230141430.

The previous prime is 40230141373. The next prime is 40230141433. The reversal of 40230141431 is 13414103204.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40230141431 - 222 = 40225947127 is a prime.

It is a super-3 number, since 3×402301414313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 40230141433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 40230141397 and 40230141406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40230141433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20115070715 + 20115070716.

It is an arithmetic number, because the mean of its divisors is an integer number (20115070716).

Almost surely, 240230141431 is an apocalyptic number.

40230141431 is a deficient number, since it is larger than the sum of its proper divisors (1).

40230141431 is an equidigital number, since it uses as much as digits as its factorization.

40230141431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 40230141431 its reverse (13414103204), we get a palindrome (53644244635).

The spelling of 40230141431 in words is "forty billion, two hundred thirty million, one hundred forty-one thousand, four hundred thirty-one".