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4023020034149 is a prime number
BaseRepresentation
bin111010100010101110101…
…011100001100001100101
3112020121010011221121012112
4322202232223201201211
51011403121112043044
612320052213130405
7563440121033234
oct72425653414145
915217104847175
104023020034149
111311175a24a86
1254b831329a05
132324a508070c
14dca02764b1b
156e9abe2609e
hex3a8aeae1865

4023020034149 has 2 divisors, whose sum is σ = 4023020034150. Its totient is φ = 4023020034148.

The previous prime is 4023020034139. The next prime is 4023020034157. The reversal of 4023020034149 is 9414300203204.

4023020034149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2577598140100 + 1445421894049 = 1605490^2 + 1202257^2 .

It is a cyclic number.

It is not a de Polignac number, because 4023020034149 - 236 = 3954300557413 is a prime.

It is a super-3 number, since 3×40230200341493 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4023020034109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011510017074 + 2011510017075.

It is an arithmetic number, because the mean of its divisors is an integer number (2011510017075).

Almost surely, 24023020034149 is an apocalyptic number.

It is an amenable number.

4023020034149 is a deficient number, since it is larger than the sum of its proper divisors (1).

4023020034149 is an equidigital number, since it uses as much as digits as its factorization.

4023020034149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 32.

The spelling of 4023020034149 in words is "four trillion, twenty-three billion, twenty million, thirty-four thousand, one hundred forty-nine".