Base | Representation |
---|---|
bin | 111010100010111011011… |
… | …011110000000111100111 |
3 | 112020121200002120100212202 |
4 | 322202323123300013213 |
5 | 1011404040401102211 |
6 | 12320125335205115 |
7 | 563445326531336 |
oct | 72427333600747 |
9 | 15217602510782 |
10 | 4023234003431 |
11 | 13112757892a5 |
12 | 54b890b1679b |
13 | 23250a4b9166 |
14 | dca22d41d1d |
15 | 6e9c0ade53b |
hex | 3a8bb6f01e7 |
4023234003431 has 2 divisors, whose sum is σ = 4023234003432. Its totient is φ = 4023234003430.
The previous prime is 4023234003407. The next prime is 4023234003433. The reversal of 4023234003431 is 1343004323204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4023234003431 - 26 = 4023234003367 is a prime.
It is a super-2 number, since 2×40232340034312 (a number of 26 digits) contains 22 as substring.
Together with 4023234003433, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 4023234003394 and 4023234003403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4023234003433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011617001715 + 2011617001716.
It is an arithmetic number, because the mean of its divisors is an integer number (2011617001716).
Almost surely, 24023234003431 is an apocalyptic number.
4023234003431 is a deficient number, since it is larger than the sum of its proper divisors (1).
4023234003431 is an equidigital number, since it uses as much as digits as its factorization.
4023234003431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 4023234003431 its reverse (1343004323204), we get a palindrome (5366238326635).
The spelling of 4023234003431 in words is "four trillion, twenty-three billion, two hundred thirty-four million, three thousand, four hundred thirty-one".
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