Base | Representation |
---|---|
bin | 111010100010111011110… |
… | …110111010000011011101 |
3 | 112020121200120222000201221 |
4 | 322202323312322003131 |
5 | 1011404044211401023 |
6 | 12320130151533341 |
7 | 563445444200251 |
oct | 72427366720335 |
9 | 15217616860657 |
10 | 4023241122013 |
11 | 1311279800623 |
12 | 54b89338a251 |
13 | 23250bb0c339 |
14 | dca23c76261 |
15 | 6e9c154885d |
hex | 3a8bbdba0dd |
4023241122013 has 2 divisors, whose sum is σ = 4023241122014. Its totient is φ = 4023241122012.
The previous prime is 4023241121971. The next prime is 4023241122053. The reversal of 4023241122013 is 3102211423204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2995852107609 + 1027389014404 = 1730853^2 + 1013602^2 .
It is a cyclic number.
It is not a de Polignac number, because 4023241122013 - 229 = 4022704251101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4023241122053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011620561006 + 2011620561007.
It is an arithmetic number, because the mean of its divisors is an integer number (2011620561007).
Almost surely, 24023241122013 is an apocalyptic number.
It is an amenable number.
4023241122013 is a deficient number, since it is larger than the sum of its proper divisors (1).
4023241122013 is an equidigital number, since it uses as much as digits as its factorization.
4023241122013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4023241122013 its reverse (3102211423204), we get a palindrome (7125452545217).
The spelling of 4023241122013 in words is "four trillion, twenty-three billion, two hundred forty-one million, one hundred twenty-two thousand, thirteen".
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