Base | Representation |
---|---|
bin | 100101011110000101… |
… | …100010000011011011 |
3 | 10211211220220001012101 |
4 | 211132011202003123 |
5 | 1124344200323141 |
6 | 30252145224231 |
7 | 2623005451333 |
oct | 453605420333 |
9 | 124756801171 |
10 | 40233214171 |
11 | 16076667327 |
12 | 796a032077 |
13 | 3a42498807 |
14 | 1d395580c3 |
15 | 10a7202531 |
hex | 95e1620db |
40233214171 has 2 divisors, whose sum is σ = 40233214172. Its totient is φ = 40233214170.
The previous prime is 40233214141. The next prime is 40233214199. The reversal of 40233214171 is 17141233204.
It is an a-pointer prime, because the next prime (40233214199) can be obtained adding 40233214171 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40233214171 - 25 = 40233214139 is a prime.
It is not a weakly prime, because it can be changed into another prime (40233214121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20116607085 + 20116607086.
It is an arithmetic number, because the mean of its divisors is an integer number (20116607086).
Almost surely, 240233214171 is an apocalyptic number.
40233214171 is a deficient number, since it is larger than the sum of its proper divisors (1).
40233214171 is an equidigital number, since it uses as much as digits as its factorization.
40233214171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 40233214171 its reverse (17141233204), we get a palindrome (57374447375).
The spelling of 40233214171 in words is "forty billion, two hundred thirty-three million, two hundred fourteen thousand, one hundred seventy-one".
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