Base | Representation |
---|---|
bin | 111010100011101001001… |
… | …010000010110001000101 |
3 | 112020200122120000120121002 |
4 | 322203221022002301011 |
5 | 1011412123241110112 |
6 | 12320333421103045 |
7 | 563503333051004 |
oct | 72435112026105 |
9 | 15220576016532 |
10 | 4024001113157 |
11 | 13116297a5183 |
12 | 54ba659b7a85 |
13 | 2326003c463c |
14 | dca96b88c3b |
15 | 6ea1811b1c2 |
hex | 3a8e9282c45 |
4024001113157 has 2 divisors, whose sum is σ = 4024001113158. Its totient is φ = 4024001113156.
The previous prime is 4024001113049. The next prime is 4024001113159. The reversal of 4024001113157 is 7513111004204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2758103848516 + 1265897264641 = 1660754^2 + 1125121^2 .
It is a cyclic number.
It is not a de Polignac number, because 4024001113157 - 212 = 4024001109061 is a prime.
Together with 4024001113159, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4024001113159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012000556578 + 2012000556579.
It is an arithmetic number, because the mean of its divisors is an integer number (2012000556579).
Almost surely, 24024001113157 is an apocalyptic number.
It is an amenable number.
4024001113157 is a deficient number, since it is larger than the sum of its proper divisors (1).
4024001113157 is an equidigital number, since it uses as much as digits as its factorization.
4024001113157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3360, while the sum is 29.
The spelling of 4024001113157 in words is "four trillion, twenty-four billion, one million, one hundred thirteen thousand, one hundred fifty-seven".
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