Base | Representation |
---|---|
bin | 100101011110101000… |
… | …001111111100010111 |
3 | 10211212120000102020021 |
4 | 211132220033330113 |
5 | 1124404013040111 |
6 | 30253112250011 |
7 | 2623146014422 |
oct | 453650177427 |
9 | 124776012207 |
10 | 40242315031 |
11 | 160808129a6 |
12 | 79710a0907 |
13 | 3a44334039 |
14 | 1d3a8469b9 |
15 | 10a7dedd71 |
hex | 95ea0ff17 |
40242315031 has 2 divisors, whose sum is σ = 40242315032. Its totient is φ = 40242315030.
The previous prime is 40242314971. The next prime is 40242315037. The reversal of 40242315031 is 13051324204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40242315031 - 217 = 40242183959 is a prime.
It is a super-2 number, since 2×402423150312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40242314987 and 40242315005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40242315037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20121157515 + 20121157516.
It is an arithmetic number, because the mean of its divisors is an integer number (20121157516).
Almost surely, 240242315031 is an apocalyptic number.
40242315031 is a deficient number, since it is larger than the sum of its proper divisors (1).
40242315031 is an equidigital number, since it uses as much as digits as its factorization.
40242315031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 40242315031 its reverse (13051324204), we get a palindrome (53293639235).
The spelling of 40242315031 in words is "forty billion, two hundred forty-two million, three hundred fifteen thousand, thirty-one".
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