Base | Representation |
---|---|
bin | 111010100011111011110… |
… | …100111000000100000001 |
3 | 112020201110101101201020111 |
4 | 322203323310320010001 |
5 | 1011413243432101033 |
6 | 12320424450311321 |
7 | 563514155262466 |
oct | 72437364700401 |
9 | 15221411351214 |
10 | 4024314331393 |
11 | 131177a587724 |
12 | 54bb32888541 |
13 | 23265026ca85 |
14 | dcac65dd66d |
15 | 6ea3588b7cd |
hex | 3a8fbd38101 |
4024314331393 has 2 divisors, whose sum is σ = 4024314331394. Its totient is φ = 4024314331392.
The previous prime is 4024314331391. The next prime is 4024314331397. The reversal of 4024314331393 is 3931334134204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3620297733264 + 404016598129 = 1902708^2 + 635623^2 .
It is a cyclic number.
It is not a de Polignac number, because 4024314331393 - 21 = 4024314331391 is a prime.
Together with 4024314331391, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4024314331391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012157165696 + 2012157165697.
It is an arithmetic number, because the mean of its divisors is an integer number (2012157165697).
Almost surely, 24024314331393 is an apocalyptic number.
It is an amenable number.
4024314331393 is a deficient number, since it is larger than the sum of its proper divisors (1).
4024314331393 is an equidigital number, since it uses as much as digits as its factorization.
4024314331393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 40.
Adding to 4024314331393 its reverse (3931334134204), we get a palindrome (7955648465597).
The spelling of 4024314331393 in words is "four trillion, twenty-four billion, three hundred fourteen million, three hundred thirty-one thousand, three hundred ninety-three".
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