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4024314331397 is a prime number
BaseRepresentation
bin111010100011111011110…
…100111000000100000101
3112020201110101101201020122
4322203323310320010011
51011413243432101042
612320424450311325
7563514155262503
oct72437364700405
915221411351218
104024314331397
11131177a587728
1254bb32888545
1323265026ca89
14dcac65dd673
156ea3588b7d2
hex3a8fbd38105

4024314331397 has 2 divisors, whose sum is σ = 4024314331398. Its totient is φ = 4024314331396.

The previous prime is 4024314331393. The next prime is 4024314331441. The reversal of 4024314331397 is 7931334134204.

4024314331397 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (4024314331441) can be obtained adding 4024314331397 to its sum of digits (44).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4024300796356 + 13535041 = 2006066^2 + 3679^2 .

It is a cyclic number.

It is not a de Polignac number, because 4024314331397 - 22 = 4024314331393 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4024314331391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2012157165698 + 2012157165699.

It is an arithmetic number, because the mean of its divisors is an integer number (2012157165699).

Almost surely, 24024314331397 is an apocalyptic number.

It is an amenable number.

4024314331397 is a deficient number, since it is larger than the sum of its proper divisors (1).

4024314331397 is an equidigital number, since it uses as much as digits as its factorization.

4024314331397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 653184, while the sum is 44.

The spelling of 4024314331397 in words is "four trillion, twenty-four billion, three hundred fourteen million, three hundred thirty-one thousand, three hundred ninety-seven".