Base | Representation |
---|---|
bin | 10010010011100101100010… |
… | …10001111010100001100011 |
3 | 12021112101020120200121121222 |
4 | 21021302301101322201203 |
5 | 20234021033341332012 |
6 | 221341025023005255 |
7 | 11323233350150021 |
oct | 1111626121724143 |
9 | 167471216617558 |
10 | 40255407761507 |
11 | 1191024a252604 |
12 | 462192673982b |
13 | 19600b7b13523 |
14 | 9d252d1b3711 |
15 | 49c207685972 |
hex | 249cb147a863 |
40255407761507 has 2 divisors, whose sum is σ = 40255407761508. Its totient is φ = 40255407761506.
The previous prime is 40255407761479. The next prime is 40255407761509. The reversal of 40255407761507 is 70516770455204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40255407761507 - 220 = 40255406712931 is a prime.
It is a super-2 number, since 2×402554077615072 (a number of 28 digits) contains 22 as substring.
Together with 40255407761509, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (40255407761509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20127703880753 + 20127703880754.
It is an arithmetic number, because the mean of its divisors is an integer number (20127703880754).
Almost surely, 240255407761507 is an apocalyptic number.
40255407761507 is a deficient number, since it is larger than the sum of its proper divisors (1).
40255407761507 is an equidigital number, since it uses as much as digits as its factorization.
40255407761507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8232000, while the sum is 53.
The spelling of 40255407761507 in words is "forty trillion, two hundred fifty-five billion, four hundred seven million, seven hundred sixty-one thousand, five hundred seven".
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