Base | Representation |
---|---|
bin | 10010010100001001001010… |
… | …01111011111010100001011 |
3 | 12021121012121110111010012102 |
4 | 21022010211033133110023 |
5 | 20234324220441331021 |
6 | 221353510510304015 |
7 | 11324511322245014 |
oct | 1112044517372413 |
9 | 167535543433172 |
10 | 40274533152011 |
11 | 11918374011564 |
12 | 46255837b800b |
13 | 1961b45244642 |
14 | 9d342526c00b |
15 | 49c97673d00b |
hex | 24a1253df50b |
40274533152011 has 2 divisors, whose sum is σ = 40274533152012. Its totient is φ = 40274533152010.
The previous prime is 40274533151981. The next prime is 40274533152017. The reversal of 40274533152011 is 11025133547204.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40274533152011 is a prime.
It is a super-2 number, since 2×402745331520112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40274533152017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20137266576005 + 20137266576006.
It is an arithmetic number, because the mean of its divisors is an integer number (20137266576006).
Almost surely, 240274533152011 is an apocalyptic number.
40274533152011 is a deficient number, since it is larger than the sum of its proper divisors (1).
40274533152011 is an equidigital number, since it uses as much as digits as its factorization.
40274533152011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 38.
Adding to 40274533152011 its reverse (11025133547204), we get a palindrome (51299666699215).
The spelling of 40274533152011 in words is "forty trillion, two hundred seventy-four billion, five hundred thirty-three million, one hundred fifty-two thousand, eleven".
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