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40274533151981 is a prime number
BaseRepresentation
bin10010010100001001001010…
…01111011111010011101101
312021121012121110111010011022
421022010211033133103231
520234324220441330411
6221353510510303525
711324511322244642
oct1112044517372355
9167535543433138
1040274533151981
1111918374011537
1246255837b7ba5
131961b4524461b
149d342526bdc9
1549c97673cedb
hex24a1253df4ed

40274533151981 has 2 divisors, whose sum is σ = 40274533151982. Its totient is φ = 40274533151980.

The previous prime is 40274533151977. The next prime is 40274533152011. The reversal of 40274533151981 is 18915133547204.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23339382277225 + 16935150874756 = 4831085^2 + 4115234^2 .

It is a cyclic number.

It is not a de Polignac number, because 40274533151981 - 22 = 40274533151977 is a prime.

It is a super-2 number, since 2×402745331519812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40274533159981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20137266575990 + 20137266575991.

It is an arithmetic number, because the mean of its divisors is an integer number (20137266575991).

Almost surely, 240274533151981 is an apocalyptic number.

It is an amenable number.

40274533151981 is a deficient number, since it is larger than the sum of its proper divisors (1).

40274533151981 is an equidigital number, since it uses as much as digits as its factorization.

40274533151981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3628800, while the sum is 53.

The spelling of 40274533151981 in words is "forty trillion, two hundred seventy-four billion, five hundred thirty-three million, one hundred fifty-one thousand, nine hundred eighty-one".