Base | Representation |
---|---|
bin | 10010010100001010111100… |
… | …11101101010111111100011 |
3 | 12021121022002100221010220121 |
4 | 21022011132131222333203 |
5 | 20234333202222434141 |
6 | 221354150043021111 |
7 | 11324544160260466 |
oct | 1112053635527743 |
9 | 167538070833817 |
10 | 40275493171171 |
11 | 11918816a08125 |
12 | 46257b120a797 |
13 | 1961c690c390b |
14 | 9d34b696d2dd |
15 | 49c9d0b731d1 |
hex | 24a15e76afe3 |
40275493171171 has 2 divisors, whose sum is σ = 40275493171172. Its totient is φ = 40275493171170.
The previous prime is 40275493171169. The next prime is 40275493171211. The reversal of 40275493171171 is 17117139457204.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40275493171171 - 21 = 40275493171169 is a prime.
It is a super-2 number, since 2×402754931711712 (a number of 28 digits) contains 22 as substring.
Together with 40275493171169, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (40275493171471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20137746585585 + 20137746585586.
It is an arithmetic number, because the mean of its divisors is an integer number (20137746585586).
Almost surely, 240275493171171 is an apocalyptic number.
40275493171171 is a deficient number, since it is larger than the sum of its proper divisors (1).
40275493171171 is an equidigital number, since it uses as much as digits as its factorization.
40275493171171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1481760, while the sum is 52.
The spelling of 40275493171171 in words is "forty trillion, two hundred seventy-five billion, four hundred ninety-three million, one hundred seventy-one thousand, one hundred seventy-one".
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