Base | Representation |
---|---|
bin | 100101100010000100… |
… | …100000001010111101 |
3 | 10212000120122211002021 |
4 | 211202010200022331 |
5 | 1130013303200211 |
6 | 30302534000141 |
7 | 2624446541263 |
oct | 454204401275 |
9 | 125016584067 |
10 | 40300053181 |
11 | 16100369483 |
12 | 79884a6051 |
13 | 3a5329b61b |
14 | 1d44396433 |
15 | 10ad006771 |
hex | 9621202bd |
40300053181 has 2 divisors, whose sum is σ = 40300053182. Its totient is φ = 40300053180.
The previous prime is 40300053169. The next prime is 40300053247. The reversal of 40300053181 is 18135000304.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37235877156 + 3064176025 = 192966^2 + 55355^2 .
It is a cyclic number.
It is not a de Polignac number, because 40300053181 - 213 = 40300044989 is a prime.
It is a super-2 number, since 2×403000531812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40300053161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20150026590 + 20150026591.
It is an arithmetic number, because the mean of its divisors is an integer number (20150026591).
Almost surely, 240300053181 is an apocalyptic number.
It is an amenable number.
40300053181 is a deficient number, since it is larger than the sum of its proper divisors (1).
40300053181 is an equidigital number, since it uses as much as digits as its factorization.
40300053181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 40300053181 its reverse (18135000304), we get a palindrome (58435053485).
The spelling of 40300053181 in words is "forty billion, three hundred million, fifty-three thousand, one hundred eighty-one".
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