Base | Representation |
---|---|
bin | 111010101010100010011… |
… | …101100110010111101111 |
3 | 112021101202112201120222101 |
4 | 322222202131212113233 |
5 | 1012022304134220413 |
6 | 12324000223555531 |
7 | 564154655015365 |
oct | 72524235462757 |
9 | 15241675646871 |
10 | 4031404991983 |
11 | 13147890239a6 |
12 | 55139145bba7 |
13 | 233210299525 |
14 | dd19a1d9635 |
15 | 6eced112edd |
hex | 3aaa27665ef |
4031404991983 has 2 divisors, whose sum is σ = 4031404991984. Its totient is φ = 4031404991982.
The previous prime is 4031404991981. The next prime is 4031404992001. The reversal of 4031404991983 is 3891994041304.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4031404991983 - 21 = 4031404991981 is a prime.
Together with 4031404991981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4031404991981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2015702495991 + 2015702495992.
It is an arithmetic number, because the mean of its divisors is an integer number (2015702495992).
Almost surely, 24031404991983 is an apocalyptic number.
4031404991983 is a deficient number, since it is larger than the sum of its proper divisors (1).
4031404991983 is an equidigital number, since it uses as much as digits as its factorization.
4031404991983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3359232, while the sum is 55.
The spelling of 4031404991983 in words is "four trillion, thirty-one billion, four hundred four million, nine hundred ninety-one thousand, nine hundred eighty-three".
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