Base | Representation |
---|---|
bin | 111010101011000111110… |
… | …011001010111111101101 |
3 | 112021110101012102121201221 |
4 | 322223013303022333231 |
5 | 1012030100014412023 |
6 | 12324142322103341 |
7 | 564206332310464 |
oct | 72530763127755 |
9 | 15243335377657 |
10 | 4032031404013 |
11 | 1314a7a681598 |
12 | 5515271aab51 |
13 | 2332accb1c32 |
14 | dd2194999db |
15 | 6ed380eb85d |
hex | 3aac7ccafed |
4032031404013 has 2 divisors, whose sum is σ = 4032031404014. Its totient is φ = 4032031404012.
The previous prime is 4032031404001. The next prime is 4032031404017. The reversal of 4032031404013 is 3104041302304.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2236825342404 + 1795206061609 = 1495602^2 + 1339853^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4032031404013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4032031404017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016015702006 + 2016015702007.
It is an arithmetic number, because the mean of its divisors is an integer number (2016015702007).
Almost surely, 24032031404013 is an apocalyptic number.
It is an amenable number.
4032031404013 is a deficient number, since it is larger than the sum of its proper divisors (1).
4032031404013 is an equidigital number, since it uses as much as digits as its factorization.
4032031404013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 4032031404013 its reverse (3104041302304), we get a palindrome (7136072706317).
The spelling of 4032031404013 in words is "four trillion, thirty-two billion, thirty-one million, four hundred four thousand, thirteen".
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