Base | Representation |
---|---|
bin | 111010101011000111110… |
… | …101100110110000001001 |
3 | 112021110101020122000212211 |
4 | 322223013311212300021 |
5 | 1012030100200320433 |
6 | 12324142343505121 |
7 | 564206340605464 |
oct | 72530765466011 |
9 | 15243336560784 |
10 | 4032032041993 |
11 | 1314a7aa7794a |
12 | 5515274581a1 |
13 | 2332b0176437 |
14 | dd2195c42db |
15 | 6ed381c58cd |
hex | 3aac7d66c09 |
4032032041993 has 2 divisors, whose sum is σ = 4032032041994. Its totient is φ = 4032032041992.
The previous prime is 4032032041991. The next prime is 4032032042029. The reversal of 4032032041993 is 3991402302304.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3017596317129 + 1014435724864 = 1737123^2 + 1007192^2 .
It is a cyclic number.
It is not a de Polignac number, because 4032032041993 - 21 = 4032032041991 is a prime.
Together with 4032032041991, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4032032041991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016016020996 + 2016016020997.
It is an arithmetic number, because the mean of its divisors is an integer number (2016016020997).
Almost surely, 24032032041993 is an apocalyptic number.
It is an amenable number.
4032032041993 is a deficient number, since it is larger than the sum of its proper divisors (1).
4032032041993 is an equidigital number, since it uses as much as digits as its factorization.
4032032041993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 40.
The spelling of 4032032041993 in words is "four trillion, thirty-two billion, thirty-two million, forty-one thousand, nine hundred ninety-three".
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