Base | Representation |
---|---|
bin | 111010101101000011110… |
… | …000101111010110110111 |
3 | 112021122202010211012221222 |
4 | 322231003300233112313 |
5 | 1012043324423010203 |
6 | 12325124534100555 |
7 | 564312014632505 |
oct | 72550360572667 |
9 | 15248663735858 |
10 | 4034111141303 |
11 | 131594762aa41 |
12 | 551a077aa75b |
13 | 233551b26c09 |
14 | dd37578d675 |
15 | 6ee0a9b0038 |
hex | 3ab43c2f5b7 |
4034111141303 has 2 divisors, whose sum is σ = 4034111141304. Its totient is φ = 4034111141302.
The previous prime is 4034111141299. The next prime is 4034111141329. The reversal of 4034111141303 is 3031411114304.
It is an a-pointer prime, because the next prime (4034111141329) can be obtained adding 4034111141303 to its sum of digits (26).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4034111141303 - 22 = 4034111141299 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4034111141393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2017055570651 + 2017055570652.
It is an arithmetic number, because the mean of its divisors is an integer number (2017055570652).
Almost surely, 24034111141303 is an apocalyptic number.
4034111141303 is a deficient number, since it is larger than the sum of its proper divisors (1).
4034111141303 is an equidigital number, since it uses as much as digits as its factorization.
4034111141303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 4034111141303 its reverse (3031411114304), we get a palindrome (7065522255607).
The spelling of 4034111141303 in words is "four trillion, thirty-four billion, one hundred eleven million, one hundred forty-one thousand, three hundred three".
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