4034122102181 has 2 divisors, whose sum is σ = 4034122102182. Its totient is φ = 4034122102180.

The previous prime is 4034122102141. The next prime is 4034122102183. The reversal of 4034122102181 is 1812012214304.

4034122102181 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3708127922500 + 325994179681 = 1925650^2 + 570959^2 .

It is a cyclic number.

It is not a de Polignac number, because 4034122102181 - 2²⁶ = 4034054993317 is a prime.

It is a super-4 number, since 4×4034122102181⁴ (a number of 52 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 4034122102183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4034122102183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2017061051090 + 2017061051091.

It is an arithmetic number, because the mean of its divisors is an integer number (2017061051091).

Almost surely, 2^{4034122102181} is an apocalyptic number.

It is an amenable number.

4034122102181 is a deficient number, since it is larger than the sum of its proper divisors (1).

4034122102181 is an equidigital number, since it uses as much as digits as its factorization.

4034122102181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 29.

Adding to 4034122102181 its reverse (1812012214304), we get a palindrome (5846134316485).

The spelling of 4034122102181 in words is "four trillion, thirty-four billion, one hundred twenty-two million, one hundred two thousand, one hundred eighty-one".