Base | Representation |
---|---|
bin | 111010101101000101000… |
… | …000011011011101101101 |
3 | 112021122210121010112201002 |
4 | 322231011000123131231 |
5 | 1012043400300000331 |
6 | 12325131001530045 |
7 | 564312360326426 |
oct | 72550500333555 |
9 | 15248717115632 |
10 | 4034132031341 |
11 | 13159583a8a35 |
12 | 551a127a3925 |
13 | 23355625c499 |
14 | dd37846a64d |
15 | 6ee0c7399cb |
hex | 3ab4501b76d |
4034132031341 has 2 divisors, whose sum is σ = 4034132031342. Its totient is φ = 4034132031340.
The previous prime is 4034132031313. The next prime is 4034132031361. The reversal of 4034132031341 is 1431302314304.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3514537584100 + 519594447241 = 1874710^2 + 720829^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4034132031341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4034132031361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2017066015670 + 2017066015671.
It is an arithmetic number, because the mean of its divisors is an integer number (2017066015671).
Almost surely, 24034132031341 is an apocalyptic number.
It is an amenable number.
4034132031341 is a deficient number, since it is larger than the sum of its proper divisors (1).
4034132031341 is an equidigital number, since it uses as much as digits as its factorization.
4034132031341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 4034132031341 its reverse (1431302314304), we get a palindrome (5465434345645).
The spelling of 4034132031341 in words is "four trillion, thirty-four billion, one hundred thirty-two million, thirty-one thousand, three hundred forty-one".
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