Base | Representation |
---|---|
bin | 10010010110001001010110… |
… | …11010000111110001000011 |
3 | 12021211210020211222001200122 |
4 | 21023010223122013301003 |
5 | 20241441143124013141 |
6 | 221445252032410455 |
7 | 11332465654416305 |
oct | 1113045332076103 |
9 | 167753224861618 |
10 | 40343356079171 |
11 | 11944580837362 |
12 | 46369903a6a2b |
13 | 1968492864392 |
14 | 9d68b3801975 |
15 | 49e65384164b |
hex | 24b12b687c43 |
40343356079171 has 2 divisors, whose sum is σ = 40343356079172. Its totient is φ = 40343356079170.
The previous prime is 40343356079137. The next prime is 40343356079237. The reversal of 40343356079171 is 17197065334304.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40343356079171 - 222 = 40343351884867 is a prime.
It is not a weakly prime, because it can be changed into another prime (40343356039171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20171678039585 + 20171678039586.
It is an arithmetic number, because the mean of its divisors is an integer number (20171678039586).
Almost surely, 240343356079171 is an apocalyptic number.
40343356079171 is a deficient number, since it is larger than the sum of its proper divisors (1).
40343356079171 is an equidigital number, since it uses as much as digits as its factorization.
40343356079171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5715360, while the sum is 53.
The spelling of 40343356079171 in words is "forty trillion, three hundred forty-three billion, three hundred fifty-six million, seventy-nine thousand, one hundred seventy-one".
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