Base | Representation |
---|---|
bin | 1111000010011011… |
… | …1011110110111101 |
3 | 101102022211120012002 |
4 | 3300212323312331 |
5 | 31231401112433 |
6 | 1504321152045 |
7 | 202014465614 |
oct | 36046736675 |
9 | 11368746162 |
10 | 4036738493 |
11 | 17916a7417 |
12 | 947a8b625 |
13 | 4c4415878 |
14 | 2a419887b |
15 | 1895d09e8 |
hex | f09bbdbd |
4036738493 has 2 divisors, whose sum is σ = 4036738494. Its totient is φ = 4036738492.
The previous prime is 4036738483. The next prime is 4036738567. The reversal of 4036738493 is 3948376304.
4036738493 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2973848089 + 1062890404 = 54533^2 + 32602^2 .
It is a cyclic number.
It is not a de Polignac number, because 4036738493 - 212 = 4036734397 is a prime.
It is a super-2 number, since 2×40367384932 = 32590515321735822098, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4036738463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2018369246 + 2018369247.
It is an arithmetic number, because the mean of its divisors is an integer number (2018369247).
Almost surely, 24036738493 is an apocalyptic number.
It is an amenable number.
4036738493 is a deficient number, since it is larger than the sum of its proper divisors (1).
4036738493 is an equidigital number, since it uses as much as digits as its factorization.
4036738493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1306368, while the sum is 47.
The square root of 4036738493 is about 63535.3326346845. The cubic root of 4036738493 is about 1592.2461421990.
The spelling of 4036738493 in words is "four billion, thirty-six million, seven hundred thirty-eight thousand, four hundred ninety-three".
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