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404012724413 is a prime number
BaseRepresentation
bin1011110000100010000…
…10001111000010111101
31102121211100012220001112
411320101002033002331
523104404224140123
6505333442451405
741121545332004
oct5702102170275
91377740186045
10404012724413
11146382717671
1266373063b65
132c137a9669c
14157a90a9c3b
15a798d33d78
hex5e1108f0bd

404012724413 has 2 divisors, whose sum is σ = 404012724414. Its totient is φ = 404012724412.

The previous prime is 404012724371. The next prime is 404012724433. The reversal of 404012724413 is 314427210404.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 400539625924 + 3473098489 = 632882^2 + 58933^2 .

It is a cyclic number.

It is not a de Polignac number, because 404012724413 - 228 = 403744288957 is a prime.

It is a super-2 number, since 2×4040127244132 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 404012724413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (404012724433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202006362206 + 202006362207.

It is an arithmetic number, because the mean of its divisors is an integer number (202006362207).

Almost surely, 2404012724413 is an apocalyptic number.

It is an amenable number.

404012724413 is a deficient number, since it is larger than the sum of its proper divisors (1).

404012724413 is an equidigital number, since it uses as much as digits as its factorization.

404012724413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21504, while the sum is 32.

Adding to 404012724413 its reverse (314427210404), we get a palindrome (718439934817).

The spelling of 404012724413 in words is "four hundred four billion, twelve million, seven hundred twenty-four thousand, four hundred thirteen".