4041012113 has 2 divisors, whose sum is σ = 4041012114. Its totient is φ = 4041012112.

The previous prime is 4041012077. The next prime is 4041012127. The reversal of 4041012113 is 3112101404.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2728181824 + 1312830289 = 52232^2 + 36233^2 .

It is a cyclic number.

It is not a de Polignac number, because 4041012113 - 2¹⁰ = 4041011089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4041012091 and 4041012100.

It is not a weakly prime, because it can be changed into another prime (4041012713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020506056 + 2020506057.

It is an arithmetic number, because the mean of its divisors is an integer number (2020506057).

Almost surely, 2^4041012113 is an apocalyptic number.

It is an amenable number.

4041012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4041012113 is an equidigital number, since it uses as much as digits as its factorization.

4041012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 4041012113 is about 63568.9555758155. The cubic root of 4041012113 is about 1592.8078378237.

Adding to 4041012113 its reverse (3112101404), we get a palindrome (7153113517).

The spelling of 4041012113 in words is "four billion, forty-one million, twelve thousand, one hundred thirteen".