Base | Representation |
---|---|
bin | 111010110011100010010… |
… | …001001000000010111111 |
3 | 112022022200210111002100222 |
4 | 322303202101020002333 |
5 | 1012202100220222323 |
6 | 12332235000011555 |
7 | 564646240064642 |
oct | 72634221100277 |
9 | 15268623432328 |
10 | 4041065398463 |
11 | 1318896081305 |
12 | 553228760bbb |
13 | 2340bc805392 |
14 | dd8351dda59 |
15 | 701b62909c8 |
hex | 3ace24480bf |
4041065398463 has 2 divisors, whose sum is σ = 4041065398464. Its totient is φ = 4041065398462.
The previous prime is 4041065398379. The next prime is 4041065398631. The reversal of 4041065398463 is 3648935601404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4041065398463 - 212 = 4041065394367 is a prime.
It is a super-3 number, since 3×40410653984633 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4041065397463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020532699231 + 2020532699232.
It is an arithmetic number, because the mean of its divisors is an integer number (2020532699232).
Almost surely, 24041065398463 is an apocalyptic number.
4041065398463 is a deficient number, since it is larger than the sum of its proper divisors (1).
4041065398463 is an equidigital number, since it uses as much as digits as its factorization.
4041065398463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7464960, while the sum is 53.
The spelling of 4041065398463 in words is "four trillion, forty-one billion, sixty-five million, three hundred ninety-eight thousand, four hundred sixty-three".
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