Base | Representation |
---|---|
bin | 111010110011100010010… |
… | …001001000100010111111 |
3 | 112022022200210111012011211 |
4 | 322303202101020202333 |
5 | 1012202100220304021 |
6 | 12332235000025251 |
7 | 564646240103626 |
oct | 72634221104277 |
9 | 15268623435154 |
10 | 4041065400511 |
11 | 13188960828a7 |
12 | 553228762227 |
13 | 2340bc8062a9 |
14 | dd8352006bd |
15 | 701b62913e1 |
hex | 3ace24488bf |
4041065400511 has 2 divisors, whose sum is σ = 4041065400512. Its totient is φ = 4041065400510.
The previous prime is 4041065400457. The next prime is 4041065400527. The reversal of 4041065400511 is 1150045601404.
4041065400511 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4041065400511 - 211 = 4041065398463 is a prime.
It is a super-2 number, since 2×40410654005112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4041065470511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020532700255 + 2020532700256.
It is an arithmetic number, because the mean of its divisors is an integer number (2020532700256).
Almost surely, 24041065400511 is an apocalyptic number.
4041065400511 is a deficient number, since it is larger than the sum of its proper divisors (1).
4041065400511 is an equidigital number, since it uses as much as digits as its factorization.
4041065400511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 31.
The spelling of 4041065400511 in words is "four trillion, forty-one billion, sixty-five million, four hundred thousand, five hundred eleven".
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