Base | Representation |
---|---|
bin | 111010110011110001101… |
… | …100100010110001010011 |
3 | 112022100100211112210202121 |
4 | 322303301230202301103 |
5 | 1012203113001302201 |
6 | 12332320403555111 |
7 | 564655532200543 |
oct | 72636154426123 |
9 | 15270324483677 |
10 | 4041324244051 |
11 | 1318a091a6886 |
12 | 55329b38ba97 |
13 | 234131324053 |
14 | dd85b73d323 |
15 | 701cdd709a1 |
hex | 3acf1b22c53 |
4041324244051 has 2 divisors, whose sum is σ = 4041324244052. Its totient is φ = 4041324244050.
The previous prime is 4041324244039. The next prime is 4041324244063. The reversal of 4041324244051 is 1504424231404.
It is a balanced prime because it is at equal distance from previous prime (4041324244039) and next prime (4041324244063).
It is a cyclic number.
It is not a de Polignac number, because 4041324244051 - 27 = 4041324243923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4041324243998 and 4041324244016.
It is not a weakly prime, because it can be changed into another prime (4041324244091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020662122025 + 2020662122026.
It is an arithmetic number, because the mean of its divisors is an integer number (2020662122026).
Almost surely, 24041324244051 is an apocalyptic number.
4041324244051 is a deficient number, since it is larger than the sum of its proper divisors (1).
4041324244051 is an equidigital number, since it uses as much as digits as its factorization.
4041324244051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61440, while the sum is 34.
Adding to 4041324244051 its reverse (1504424231404), we get a palindrome (5545748475455).
The spelling of 4041324244051 in words is "four trillion, forty-one billion, three hundred twenty-four million, two hundred forty-four thousand, fifty-one".
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