4041442138241 has 2 divisors, whose sum is σ = 4041442138242. Its totient is φ = 4041442138240.

The previous prime is 4041442138231. The next prime is 4041442138243. The reversal of 4041442138241 is 1428312441404.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3013682112016 + 1027760026225 = 1735996^2 + 1013785^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4041442138241 is a prime.

Together with 4041442138243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4041442138195 and 4041442138204.

It is not a weakly prime, because it can be changed into another prime (4041442138243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020721069120 + 2020721069121.

It is an arithmetic number, because the mean of its divisors is an integer number (2020721069121).

Almost surely, 2^{4041442138241} is an apocalyptic number.

It is an amenable number.

4041442138241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4041442138241 is an equidigital number, since it uses as much as digits as its factorization.

4041442138241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 98304, while the sum is 38.

Adding to 4041442138241 its reverse (1428312441404), we get a palindrome (5469754579645).

The spelling of 4041442138241 in words is "four trillion, forty-one billion, four hundred forty-two million, one hundred thirty-eight thousand, two hundred forty-one".