Base | Representation |
---|---|
bin | 101101111101000010011001… |
… | …1100111100010011010110111 |
3 | 1222000012101201112201122002121 |
4 | 1123322010303213202122313 |
5 | 410440111434010143223 |
6 | 3551404540101220411 |
7 | 151066302002442001 |
oct | 13372046347423267 |
9 | 1860171645648077 |
10 | 404213123131063 |
11 | 107881906214024 |
12 | 39403265101707 |
13 | 144711983b945c |
14 | 71b603b8c7371 |
15 | 31ae79e6d315d |
hex | 16fa1339e26b7 |
404213123131063 has 2 divisors, whose sum is σ = 404213123131064. Its totient is φ = 404213123131062.
The previous prime is 404213123131021. The next prime is 404213123131121. The reversal of 404213123131063 is 360131321312404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 404213123131063 - 217 = 404213122999991 is a prime.
It is a super-2 number, since 2×4042131231310632 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (404213123101063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202106561565531 + 202106561565532.
It is an arithmetic number, because the mean of its divisors is an integer number (202106561565532).
Almost surely, 2404213123131063 is an apocalyptic number.
404213123131063 is a deficient number, since it is larger than the sum of its proper divisors (1).
404213123131063 is an equidigital number, since it uses as much as digits as its factorization.
404213123131063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 404213123131063 its reverse (360131321312404), we get a palindrome (764344444443467).
The spelling of 404213123131063 in words is "four hundred four trillion, two hundred thirteen billion, one hundred twenty-three million, one hundred thirty-one thousand, sixty-three".
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