4042153433111 has 2 divisors, whose sum is σ = 4042153433112. Its totient is φ = 4042153433110.

The previous prime is 4042153433027. The next prime is 4042153433141. The reversal of 4042153433111 is 1113343512404.

4042153433111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4042153433111 - 2¹⁴ = 4042153416727 is a prime.

It is a super-2 number, since 2×4042153433111² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4042153433141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021076716555 + 2021076716556.

It is an arithmetic number, because the mean of its divisors is an integer number (2021076716556).

Almost surely, 2^{4042153433111} is an apocalyptic number.

4042153433111 is a deficient number, since it is larger than the sum of its proper divisors (1).

4042153433111 is an equidigital number, since it uses as much as digits as its factorization.

4042153433111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 4042153433111 its reverse (1113343512404), we get a palindrome (5155496945515).

The spelling of 4042153433111 in words is "four trillion, forty-two billion, one hundred fifty-three million, four hundred thirty-three thousand, one hundred eleven".